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50+8x+0.01x^2=0
a = 0.01; b = 8; c = +50;
Δ = b2-4ac
Δ = 82-4·0.01·50
Δ = 62
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{62}}{2*0.01}=\frac{-8-\sqrt{62}}{0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{62}}{2*0.01}=\frac{-8+\sqrt{62}}{0.02} $
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